如图所示,正方形导线框abcd,每边长L,ab的质量为m,且质量分布均匀,其他边质量不计,导线框总电阻为R

2025-05-20 10:13:56
推荐回答(1个)
回答1:

解:(1)Q=It=N*(磁通量变化量)/R=B*S/R=B(L方)/R
(2)在最低点时,V=wL
则E=BLV=BLwL——I=E/R=B(L方)w/R
安培力F=BIL=(B方)(L三次方)w/R
(3)在最低点时,ab的向心力F=m(V方)/R=m(w方)(L方)/R
ac的拉力F=0.5F(向心力)=m(w方)(L方)/2R
(4)从水平位置到最低点,对系统用动能定理:
mgL-Q=0.5m(V方)-0
则Q=mgL-0.5m(V方)=mgL-m(w方)(L方)/2