(-2)的4次方除(2又2⼀3)的2次方+5又1⼀2(-1⼀6)-0.25的计算过程

2024-11-01 14:54:06
推荐回答(2个)
回答1:

(-2)的4次方除(2又2/3)的2次方+5又1/2*(-1/6)-0.25
=16÷(8/3)^2+11/2*(-1/6)-1/4
=16×27/64-11/12-1/4
=27/4-11/12-1/4
=13/2-11/12
=78/12-11/12
=67/12

回答2:

=16÷(8/3)^2+11/2-1/6-1/4
=16×27/64+33/6-1/6-1/4
=27/4-1/4+32/6
=13/2+16/3
=(39+32)/6
=71/6