已知(a-1)2016 |2d-3| (c 1)2=0,求ad⼀3c-a-c⼀b的值

2025-03-10 13:32:31
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回答1:

|a+1/2|+|b-1/3|+(c+2)^2=0, 所以 |a+1/2|=0,|b-1/3|=0,(c+2)^2=0, 即 a+1/2=0,b-1/3=0,c+2=0 a=-1/2,b=1/3,c=-2 (a-b)^2-b/a+ab^2/c =(-1/2-1/3)^2-1/3/(-1/2)+(-1/2)*(1/3)^2/(-2) =25/36+2/3+1/36 =13/18+12/18 =25/18.。