求不定积分∫2x-2⼀x^2-2x+3dx

求具体过程。。
2024-11-14 12:54:08
推荐回答(1个)
回答1:

∫2x-2/x^2-2x+3dx
=∫(x^2-2x+3)'/(x^2-2x+3) dx
=∫1/(x^2-2x+3) d(x^2-2x+3)
=ln(x^2-2x+3)+c