求sin20°+4tan20°的解答过程

2025-03-12 15:00:42
推荐回答(1个)
回答1:

 原式=1\\/2(1-cos40°)+1\\/2(1+cos100°)+sin20°cos50°\r\n\r\n         =1+1\\/2(cos100°-cos40°)+1\\/2(sin70°-sin30°)\r\n\r\n         =3\\/4-sin70°sin30°+1\\/2sin70°\r\n\r\n         =3\\/4