已知x=2005,y=2006,则分式(x+y)(x^2+y^2)⼀x^4-y^4

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2025-03-03 17:36:19
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回答1:

解:当x=2005,y=2006时, 原式=(x+y)(x^2+y^2)/(x-y)(x+y)(x^2+y^2) =1/(x-y) =1/(2005-2006) =-1

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