圈圆圈的题,求解,详细一些谢谢

求极限
2025-04-06 22:46:55
推荐回答(2个)
回答1:

死办法是这样的

回答2:

lim(x->∞) [2^(n+1)+3^(n+1)]/(2^n+3^n)
=lim(x->∞)(2*2^n+2*3^n+3^n)/(2^n+3^n)
=2+lim(x->∞) 3^n/(2^n+3^n)
=2+lim(x->∞) 1/[1+(2/3)^n]
=2+1
=3