极限运算问题

为什么我算出来结果不一样 同样是等价替代 sin 1/x 不能去替为1/x吗
2025-03-15 11:24:55
推荐回答(2个)
回答1:

1.极限的四则运算、任何复合运算,只要是定式之间的运算都成立; 2.出错。 3.极限不存在。 4.运用乘除法运算,乘号前后不能出现0乘以∞的情况,除法不能出现分子分母同趋于无穷大,或同趋于0的情况。 极限的运算法则:(1)直接带入法(2)无穷大与无穷小的关系例子:lim(x趋向于1)-(4x-1)/(x2+2x-3)根据无穷大无穷小的关系则为0。(3)“0/0”型未定式用因式分解法 (4)“无穷/无穷”未定式用X的最高次幂去除以每一项例子: lim(x趋向于无穷)(3x2+x+1)/(2x2+4x-3) 分子分母同除于X2得3/2

回答2:

lim(x->0) x^2. sin(1/x) / sinx
=[lim(x->0) x.sin(1/x) ][lim(x->0 (x/ sinx) ]
=(0)(1)
=0

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