解：z=i^2+√3i=-1+√3i。式中a=-1,b=√3.r=√[(-1)^2+(√3)^2]=2.cosθ=a/r=-1/2,θ=2π/3.sinθ=b/r=√3/2,θ=π/3,θ=2π/3.∴复数z的幅角的主值为2π/3.
