Android 解析 嵌套的JsonArray 这个具体该怎么解析呢?

2025-03-20 06:57:37
推荐回答(4个)
回答1:

String json = "";
try {
JSONArray arr = new JSONArray(json);
for (int i=0; i JSONObject obj = arr.getJSONObject(i);
String secondId = obj.getString("secondId");
String lessonpId = obj.getString("lessonpId");
String secondTitle = obj.getString("secondTitle");
JSONArray recordArr = obj.getJSONArray("record");
for (int j=0; j JSONObject recordObj = recordArr.getJSONObject(j);
// String secondId2 = recordObj.getString("secondId");
String threeTitle = recordObj.getString("threeTitle");
String threeId = recordObj.getString("threeId");
}
}
} catch (JSONException e) {
e.printStackTrace();
}

回答2:

完全可以,用activityGroup

回答3:

用 fastjson

回答4:

答-还是您自己算吧对您今后有好处的。