先约分原式=(1+i)^6(1-i)^6-(3-4i)[2^3(1+i)^2(1+i)](4-3i)/(4+3i)(4-3i)=[(1+i)(1-i)]^6-[(3-4i)(4-3i)[8(1+2i-1)(1+i)]/(16+9)=(1+1)^6-[(12-9i-16i-12)[16i(1+i)]/25=64-(-25i)[16i(1+i)]/25=64-16(1+i)=48-16i
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