已知x+y=7,xy=12,求(x-y)平方的值

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2025-02-27 04:37:36
推荐回答(4个)
回答1:

(x-y)²
=x²-2xy+y²
=(x+y)²-4xy
当x+y=7,xy=12时,代入得
7²-4*12=1

回答2:

(x-y)²
=x²-2xy+y²
=(x+y)²-4xy
=49-48
=1

回答3:

(x-y)^2=x^2-2xy+y^2=x^2+2xy+y^2-4xy=(x+y)^2-4xy=7^2-4*12=1

回答4:

1