log以8为底9的对数⼀log以2为底3的对数 怎么算?

2024-11-20 16:44:20
推荐回答(1个)
回答1:

换成以10为底
=(log 9/log 8)/(log 3/log 2)
= (log 9 · log 2) / (log 8 · log 3)
= (2log3 · log 2) / (3log 2 · log 3)
= 2/3