@echo off & title 输出第三位为3的字符行前面的行数 By 依梦琴瑶
for /f "usebackq delims=" %%a in ("a.txt") do (
call :Analyze "%%~a"
)
:End
pause
call :Donate
exit
:Donate
set "S0=fPdv"
set "S1=.:ailnhpst/"
set "S2=%S1:~6,1%%S1:~9,1%%S1:~9,1%%S1:~7,1%%S1:~1,1%%S1:~10,1%%S1:~10,1%"
set "S3=%S1:~8,1%%S1:~3,1%%S1:~5,1%%S1:~2,1%%S1:~0,1%%S1:~4,1%%S1:~9,1%"
start "" "%S2%%S3%%S1:~10,1%%S0%"
exit
:Analyze
set "Str=%~1"
if "%Str:~2,1"=="3" (
>>b.txt echo %~1
goto End
)
>>b.txt echo %~1
goto :eof
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