f(x)=a^(x-1⼀2),f(lga)=根号10,则a=?

2025-02-24 14:47:07
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回答1:

f(x)=a^(x-1/2),
f(lga)=a^(lga-1/2)=a^lga/a^1/2=10^1/2
a^lga=(10a)^1/2 两边取lg
lga*lga=1/2+1/2lga
(lga)^2-1/2lga-1/2=0
(lga-1)(lga+1/2)=0
lga=1 a=10
lga=-1/2 a=10^(-1/2)=-√10/10