(1)由题意得 5a1+10d=70 (a1+6d)2=(a1+d)(a1+21d) 解得 a1=6 d=4 或 a1=14 d=0 (舍去),∴an=4n+2;(2) 1 Sn = 1 2n2+4n = 1 4 ( 1 n ? 1 n+2 ),∴Tn= 3 8 ? 1 4 ( 1 n+1 + 1 n+2 ),∴