已知等差数列{an}的公差d≠0,它的前n项和为Sn,若S5=70,且a2,a7,a22成等比数列.(1)求数列{an}的通

2025-03-03 18:01:46
推荐回答(1个)
回答1:

(1)由题意得
5a1+10d=70
(a1+6d)2=(a1+d)(a1+21d)

解得
a1=6
d=4
a1=14
d=0
(舍去)

∴an=4n+2;
(2)
1
Sn
1
2n2+4n
1
4
(
1
n
?
1
n+2
)

Tn
3
8
?
1
4
(
1
n+1
+
1
n+2
)