图
解:x²-2x-2=0x=(2±√4+8)/2=1±√3x1=1+√3x2=1-√3
x+1=±√3x1=√3-1x2=-√3-1
(x-1)²=3得x^2-2x-2=0解得x=(2+2根3)/2或x=(2-2根3)/2解得x=1+根3或x=1-根3.
