自己推导一遍,就那么理解了。对参数方程 x = x(t),y = y(t),求导,得 dy/dx = y'/x',这里 x' = dx/dt,y' = dy/dt,再求导 d²y/dx² = (d/dx)(y'/x') = [(d(y'/x')/dt]/(dx/dt) = {[(dy'/dt)x'-y'(dx'/dt)]/x'²}/x' = [(y"x'-y'x")/x'³。