试确定(2+1)(2的平方+1)(2的4次方+1)(2的8次方+1)(2的16次方+1)(2的32

2025-03-10 04:34:25
推荐回答(2个)
回答1:

(2+1)(2^2+1)(2^4+1).......(2^32+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1).......(2^32+1)+1
=(2^2-1)(2^2+1)(2^4+1)....(2^32+1)+1
=(2^4-1)(2^4+1)....(2^32+1)+1
=......
=2^64-1+1
=2^64
因为2的4次方=16
所以
2的64次方的末尾数是6

(2014^5-2x2014^4-2012)/(2014^5+2014^4-2015)
=[2014^4x(2014-2)-2012]/[2014^4x(2014+1)-2015]
=(2014^4x2012-2012)/(2014^4x2015-2015)
=[2012x(2014^4-1)]/[2015x(2014^4-1)]
=2012/2015

回答2:

2012/2015