醋酸溶液中存在CH3COOH?CH3COO-+H+,加水稀释促进电离,
A.由Kw=c(H+)×c(OH-)可知,温度不变,则c(H+)c(OH-)不变,故A错误;
B.加水稀释,虽然n(H+)增大,但增大倍数明显小于体积增大倍数,则c(H+)减小,故B错误;
C.加水稀释促进电离,n(CH3COO-)和n(H+)增大,n(CH3COOH)减小,则
=c(H+) c(CH3COOH)
,应增大,故C正确;n(H+) n(CH3COOH)
D.
为醋酸的电离常数,温度不变,常数不变,故D错误.c(H+)?c(CH3COO?) c(CH3COOH)
故选:C.