用蒸馏水稀释0.1mol?L-1的醋酸至0.01mol?L-1,稀释过程中温度维持25℃不变,下列各项中始终保持增大趋势

2025-04-06 22:47:46
推荐回答(1个)
回答1:

醋酸溶液中存在CH3COOH?CH3COO-+H+,加水稀释促进电离,
A.由Kw=c(H+)×c(OH-)可知,温度不变,则c(H+)c(OH-)不变,故A错误;
B.加水稀释,虽然n(H+)增大,但增大倍数明显小于体积增大倍数,则c(H+)减小,故B错误;
C.加水稀释促进电离,n(CH3COO-)和n(H+)增大,n(CH3COOH)减小,则

c(H+)
c(CH3COOH)
=
n(H+)
n(CH3COOH)
,应增大,故C正确;
D.
c(H+)?c(CH3COO?)
c(CH3COOH)
为醋酸的电离常数,温度不变,常数不变,故D错误.
故选:C.