我来啦，答完啦记得给我悬赏耶耶耶
(1) lim1/(x-3) = ∞(2) limlnx = 0二 (1) lim(x^2+5)/(x-3) = -9(2) lim(x^2-3x+2)/(x^2-1) = lim(x-2)/(x+1) = -1/2(3) lim(x^2+x)/(x^4-2x^3+10) = lim(1/x2+1/x^4)/(1-2/x+10/x^4) = 0(4) limx^4/(3x^3+2x^2+1) = limx/(3+2/x+1/x^3) = ∞
方法如下图所示，请认真查看，祝学习愉快：
