由x+1/y=y+1/z得x-y=(y-z)/yz (1),再由x+1/y=z+1/x得x-z=1/x-1/y=(y-x)/xy,再将(1)代入得xyyz=(z-y)/(x-z) (2) 同理,xxyz=(x-y)/(y-z) (3),xyzz=(z-x)/(x-y) (4) (2)(3)(4)相乘得xyz=1x^2*y^2*z^2=1求采纳为满意回答。
