求下列函数的导数.(1)y=x 2 sinx;(2)y= ;(3) y=log 2 (2x 2 +3x+1)

求下列函数的导数.(1)y=x 2 sinx;(2)y= ;(3) y=log 2 (2x 2 +3x+1).
2025-03-10 00:54:38
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回答1:

解:(1)y′=(x 2 )′sinx+x 2 (sinx)′=2xsinx+x 2 cosx;
(2)y′=
(3)设y=log 2 u,u=2x 2 +3x+1,
则y′ x =y′ u ·u′ x = (4x+3)=