X3-y3
=x³-x²y+x²y-y³
=x²(x-y)+y(x²-y²)
=x²(x-y)+y(x+y)(x-y)
=(x-y)(x²+xy+y²)
x^3-y^3
解：原式=x^3-x^2*y+x^2*y-y^3
=x^2*(x-y)+y*(x^2-y^2)
=x^2*(x-y)+y*(x+y)*(x-y)
=(x-y)*(x^2+x*y+y^2)
是分解因式吧
x^3-y^3
=(x-y)(x^2+xy+y^2)
x^3-y^3
=x^3-x^2*y+x^2*y-y^3
=x^2*(x-y)+y*(x^2-y^2)
=x^2*(x-y)+y*(x+y)*(x-y)
=(x-y)*(x^2+x*y+y^2)
（x-y）(x2+xy+y2)
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