求解此高数题

如图
2024-07-31 00:49:59
推荐回答(2个)
回答1:

具体解答羡键,兄卜巧

如图所弊告示

回答2:

令t=-1/x,则x=-1/t
原慧敏式=lim(t->0+) [√(4/t^2+8/t+3)-a/t-b]
=lim(t->0+) [√(4+8t+3t^2)-a-bt]/t
=lim(t->告握0+) [√(t+2)(3t+2)-a-bt]/前友枝t
=lim(t->0+) [2√(1+t/2)(1+3t/2)-a-bt]/t
=lim(t->0+) {2[1+t/4+o(t)][1+3t/4+o(t)]-a-bt}/t
=lim(t->0+) [2+2t+o(t)+3t^2/8+o(t^2)-a-bt]/t
=lim(t->0+) [(2-a)+(2-b)t+3t^2/8+o(t)+o(t^2)]/t
=0
所以a=2,b=2