1.两边各自先通分,(x+5)/2=(2x+2)/3
2.分式转化为等积式, 3(x+5)=2(2x+2)
3.去括号,3x+15=4x+4
4.移项,同类项放一边,15-4=4x-3x
5.得出结论, x=11
解: (两边都乘以6)
18+3x-3 = 6-2+4x
15+3x = 4+4x
x = 11
(x-1)/2+(1-2x)/3=1-3
(3(x-1)+2(1-2x))/6=-2
3(x-1)+2(1-2x)=-12
3x-2+2-4x=-12
-x=-12
所以x=12