11ᠧ99的简便运算?

2025-04-03 21:45:43
推荐回答(4个)
回答1:

11✘99
=11x(100-1)
=11x100-11
=1100-11
=1089

回答2:

乘法分配律为:两个数的和与一个数相乘,先将它们与这个数分别相乘,再相加,积不变.即:(a+b)×c=a×c+b×c.反过来则:a×c+b×c=(a+b)×c
11×99
= 11× ( 100-1)
= 100×11-11
= 1100-11
= 1089

回答3:

11X99
=11x(99+1)
=11x100-11
=1100-11
=1089

回答4:

原式=10x99+99
=990+99
=1089