两边同时乘以x²-16+(x²-1)=3(x+1)x²+5=3x+3x²-3x+2=0(x-1)(x-2)=0x=1, 2经检验，x=1为增根，舍去x=2为原方程的根
6/(x²-1)+1=3/(x-1)6/(x+1)(x-1)+1=3/(x-1)6+(x+1)(x-1)=3(x+1)6+x²-1=3x+3x²-3x+2=0(x-1)(x-2)=0x1=1 x2=2
