已知等差数列{an}的前n项和为Sn,公差d≠0且S3+S5=50,a1,a4,a13成等比数列.则数列{an}的通项公式为__

2025-02-24 06:09:35
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回答1:

设数列的公差为d,则
∵S3+S5=50,a1,a4,a13成等比数列,
∴8a1+13d=50,(a1+3d)2=a1?(a1+12d)
∴a1=3,d=2
∴an=3+2(n-1)=2n+1
故答案为:an=2n+1.