一自藕变压器,一次绕组的匝数N1=1000匝,接到220V交流电源上,二次绕组的匝数N2=500匝

2025-03-13 08:36:06
推荐回答(2个)
回答1:

U1 : U2 = N1 : N2 U2 = U1 * N2 / N1 = 220 * 500 /1000 = 110 V

Z2 =(R*R + X*X)^0.2 = 5 I2 = U2 / Z2 = 110 / 5 = 22 A
P2 = I2 * I2* R = 1936 W

回答2:

一分钱不给?