求PHP跳转代码

2025-02-27 03:56:25
推荐回答(1个)
回答1:

我来回答吧: 我测试过 ,返回 301.

$sTrr = @explode(".", $_SERVER['SERVER_NAME']);
$domain = strtolower($sTrr[0]);

// 如果是wap网站
if ( $domain == 'wap')
{
header("HTTP/1.1 301 Moved Permanently");
header("Location: http://wap.12306.com/wap/");
exit();
}
else
{
header("HTTP/1.1 301 Moved Permanently");
header("Location: http://www.12306.com/index.php");
exit();
}
?>