解:RT△ADB和RT△A'D'B'中
∠ADB=∠A'D'B';AD=A'D';AB=A'B'
RT△ADB≌RT△A'D'B'得到BD=B'D'
BC=B'C',CD=BC-BD,C'D'=B'C'-B'D'
CD=C'D',RT△ADC和RT△A'D'C'中
∠ADB=∠A'D'B';AD=A'D';CD=C'D'
RT△ADC≌RT△A'D'C'得AC=A'C'
请采纳答案,支持我一下。
先证明直角△acd全等于直角△bcd(HL),得出∠cad=∠cbd,在证明△acb全等△bcd(ASA),ac=ac撇