解:①∵AB是⊙O的直径,弦CD⊥AB,∴DG=CG,∴弧AD=弧AC,∠ADF=∠AED,∵∠FAD=∠DAE(公共角),∴△ADF∽△AED;②∵ CF FD = 1 3 ,CF=2,∴FD=6,∴CD=DF+CF=8,∴CG=DG=4,∴FG=CG-CF=2;③∵AF=3,FG=2,∴AG= AF2?FG2 = 5 ,tan∠E= AG DG = 5 4 .