(2011?百色)如图,在△ABC中,AB=AC,∠ABC、∠ACB的平分线BD,CE相交于O点,且BD交AC于点D,CE交AB于

2025-04-27 20:00:01
推荐回答(1个)
回答1:

∵AB=AC,∴∠ABC=∠ACB.
∵BD平分∠ABC,CE平分∠ACB,
∴∠ABD=∠CBD=∠ACE=∠BCE.
∴①△BCD≌△CBE (ASA);
  ③△BDA≌△CEA (ASA);
  ④△BOE≌△COD (AAS或ASA).
故选D.