cos2x+sin2x怎么化简?-sin2x呢?(总之它们放在一起怎么处理?)

2025-04-03 12:29:19
推荐回答(3个)
回答1:

cos2x+sin2x
=√2(√2/2*cos2x+√2/2*sin2x)
=√2cos(2x-π/4)

cos2x-sin2x
=√2(√2/2*cos2x-√2/2*sin2x)
=√2cos(2x+π/4)

回答2:

cos2x+sin2x
=√2(√2/2cos2x+√2/2sin2x)
=√2sin(2x+π/4)
cos2x-sin2x
=√2(√2/2cos2x-√2/2sin2x)
=√2sin(π/4-2x)

回答3:

cos2x+sin2x=√2sin(2x+π/4)
cos2x-sin2x=√2cos(2x+π/4)