linkedlist 源代码怎么查找元素的

2025-03-16 01:16:38
推荐回答(1个)
回答1:

这个方法是可行的的,indexOf方法 比较的是通过equal方法比较的
如果你重写了equal方法,就使用你的规则进行比较,否则使用系统默认的方法即 Object中的equal方法;
给你贴个demo;

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public class Main{
public static void main(String[] args) {
LinkedList list = new LinkedList<>();
Book a = new Book(1,"a");
Book b = new Book(2,"b");
Book c = new Book(3,"c");
Book d = new Book(4,"d");
list.add(a);
list.add(b);
list.add(c);
list.add(d);

int index = list.indexOf(new Book(4, "d"));
System.out.println(index);

}
}
class Book{
int id;
String name;
public Book(int id,String name){
this.id = id;
this.name = name;
}
@Override
public boolean equals(Object obj) {
Book book = (Book) obj;
if(book!=null){
if((book.id == this.id) && (book.name.equals(this.name)))
return true;
}
return false;
}

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