2√(x2+y2)=1-x ==> 4(x2+y2)=(1-x)2=x2-2x+1 ==> 4x2+4y2-x2+2x-1=0 ==> 3x2+2x+4y2-1=0 ==> 3[x2+(2/3)x+(1/9)]+4y2-(4/3)=0 ==> 3[x+(1/3)]2+4y2=4/3 ==> (9/4)[x+(1/3)]2+3y2=1 ——这个应该是高中化简椭圆标准方程的基本内容吧！！
