∫ 2x^2⼀(1+x^2)dx 具体步骤

2025-03-05 03:17:02
推荐回答(1个)
回答1:

∫ 2x^2/(1+x^2)dx
=积分:[2(x^2+1)-2]/(1+x^2)dx
=积分:2dx-积分:2/(1+x^2)dx
=2x-2tanx+C