解：∵CE平分角ACB.∠BAC=90°AD⊥BC∴AE=EF ∠AEC=∠CEF∵.∠BAC=90°AD⊥BC∴AD∥EF∴∠AGE=∠CEF又∵.∠AEC=∠CEF∴∠AGE=∠CEF∴AG=AE∵.AE=EF∴AG=EF又∵AD∥EF即AG∥EF∴四边形AEFG是平行四边形∵.AE=EF∴四边形AEFG是菱形打字不易，请采纳，谢谢啦！
