(1)设数列{an}的公差为d,,{bn}的公比为q,据题意得
(6+d)q=16 (9+3d)q2=60
解得
d=2 q=2
∴an=3+(n-1)×2=2n+1,bn=2n-1
(2)∵anbn=(2n+1)?2n-1
∴Tn=3×20+5×2+7×22+…+(2n+1)×2n-1 ①
2Tn=+3×2+5×22+7×23+…+(2n-1)×2n-1+(2n+1)×2n ②
①-②得-Tn=3+22+23+…+2n-(2n+1)×2n
∴Tn=(2n-1)×2n+1