sinx+cosx=?

2025-03-04 06:31:50
推荐回答(2个)
回答1:

=√2(sinx*√2/2+cosx*√2/2)
=√2(sinxcosπ/4+cosxsinπ/4)
=√2sin(x+π/4)

回答2:

(x2+ax+5)·(-6x3)
=-6x^5-6ax^4-30x3
不含x的四次方项
所以系数为0
-6a=0
a=0原式=6a2-2ab-3a2-4ab+1/2b2
=3a2-6ab+1/2b2