前一步到后一步是怎么算出来的?式子怎么打开,给个完整过程吧,谢谢

2025-04-27 05:22:53
推荐回答(1个)
回答1:

公式: d(xy)=xdy+ydx d(lnx)=(1/x)dx d[ln(x-y)]=[1/(x-y)]d(x-y) 右侧: d[(x-y)(ln(x-y)] =d(x-y)ln(x-y)+(x-y)d[ln(x-y)] =(dx-dy)ln(x-y)+(x-y)/(x-y)d(x-y) =(dx-dy)ln(x-y)+d(x-y) =(dx-dy)ln(x-y)+(dx-dy)