(1)方程两边同乘以(x-2),得:(x-3)+x-2=-3,合并:2x-5=-3,解得:x=1,经检验,x=1是原方程的解;戚销(2)原式纯返= x+1?1 x+1 ?(x+1)(x-1)+(x-2)=x(x-1)+(x-2)=x2-2,当x= 6 时高裤游,原式=( 6 )2-2=4.