这样
x的三次方－3x的平方－6x+8
=(x³-4x²)+(x²-6x+8)
=x²(x-4)+(x-2)(x-4)
=(x-4)(x²+x-2)
=(x-4)(x-1)(x+2)
请采纳
f(x)=x^3-3x^2-6x+8
f(1) =1-3-6+8=0
x^3-3x^2-6x+8=(x-1)(x^2+ax-8)
coef. of x
-8-a=-6
a=-2
x^3-3x^2-6x+8
=(x-1)(x^2+2x-8)
=(x-1)(x+4)(x-2)
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