二.∮L (x²+y²)ds=∮L ds=2π三.1.∮∮Σ xdydz+ydzdx+zdxdy=∫∫∫Ω 3dxdydz=3×4/3 πR³=4πR³所以错误2.z=u²+v²u=x+y,v=x-yZy=2u·Uy+2v·Vy=2(x+y)·1+2(x-y)·(-1)=2x+2y-2x+2y=4y所以错误