解：一般二次函数为y=ax�0�5+bx+c(a≠0)y=ax�0�5+bx+c=a[x�0�5+bx/a+(b/2a)�0�5]+c-(b�0�5/4a)=a[x+(b/2a)]�0�5+(4ac-b�0�5)/4a顶点坐标为(-b/2a,(4ac-b�0�5)/4a)满意谢谢采纳，给个“能解决+原创”!
