已知x+y=1,xy=1⼀5,求x²y+xy², (x²+1)(y²+1)

2025-03-04 16:01:56
推荐回答(2个)
回答1:

x²y+xy²=xy*(x+y)=1/5
(x²+1)(y²+1) =x²y²+x²+y²+1=x²y²+(x+y)²-2xy+1=1/25+1-2/5+1=41/25

回答2:

x^2+xy^2=xy(x+y)=1/5
(x^2+1)(y^2+1)=(xy)^2+(x+y)^2-2xy+1=1/25+1-2/5+1=41/25