python 文件 路径操作问题

2025-03-26 18:10:12
推荐回答(1个)
回答1:

# ======== Select a file for opening:
import Tkinter,tkFileDialog

def choiseFile():
root = Tkinter.Tk()
return tkFileDialog.askopenfile(parent=root,mode='rb',title='Choose a file')