2(X+1)(X+2)(X+3)(X+6)+X的平方怎么因式分解

2025-03-01 17:11:57
推荐回答(1个)
回答1:

=[(x+1)(x+6)][(x+2)(x+3)]+x²
=[(x²+6)+7x][(x²+6)+5x]+x²
=(x²+6)²+12x(x²+6)+35x²+x²
=(x²+6)²+12x(x²+6)+36x²
=(x²+6x+6)²