3x的平方十6x一4二0怎么解

2024-11-13 08:54:31
推荐回答(3个)
回答1:


回答2:

3x² + 6x - 4 = 0
x² + 2x = 4/3
x² + 2x + 1 = 7/3
(x + 1)² = 7/3
x + 1 = ± √21 / 3

x = - 1 ± √21 / 3

回答3:

3x^2+6x-4=0
x=(-6±√(6^2+4*3*4))/6
x=(-3±√21)/3
望采纳,谢谢!